Checking for the existence of multiple directories

I would loop:

result=True
for dir in \
        "$PWD/dir1" \
        "$PWD/dir2" \
        "$PWD/dir3" 
do
    if ! [ -d "$dir" ]; then
        result=False
        break
    fi
done
echo "$result"

The break causes the loop to short-circuit, just like your chain of &&

A loop might be more elegant:

arr=("$PWD/dir1" "$PWD/dir2" "$PWD/dir2")
for d in "${arr[@]}"; do
    if [ -d "$d"]; then
        echo True
    else
        echo False
    fi
done

This is Bash. A more portable one is Sh. There you can use the positional array:

set -- "$PWD/dir1" "$PWD/dir2" "$PWD/dir2"

Then to loop over it use "$@".

If you already expect them to be directories and are just checking whether they all exist, you could use the exit code from the ls utility to determine whether one or more "errors occurred":

ls "$PWD/dir1" "$PWD/dir2" "$PWD/dir3" >/dev/null 2>&1 && echo All there

I redirect the output and stderr to /dev/null in order to make it disappear, since we only care about the exit code from ls, not its output. Anything that's written to /dev/null disappears — it is not written to your terminal.