RXJS Continue with concat subscribe after error

You can apply the catch operator to each of the source observables and can perform the error logging within it. Like this:

const sources = [
  Rx.Observable.from("1").delay(200),
  Rx.Observable.from("2").delay(150),
  Rx.Observable.throw("error"),
  Rx.Observable.from("3").delay(124),
  Rx.Observable.from("4").delay(201),
];
const sourcesWithCatch = sources.map(s => s.catch(e => {
  console.log(e);
  return Rx.Observable.empty();
}));
const concatted = Rx.Observable.concat(...sourcesWithCatch);
concatted.subscribe(v => console.log(v));

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<script src="https://unpkg.com/rxjs@5/bundles/Rx.min.js"></script>

For future reference, Rxjs 5 has the onErrorResumeNext function that behaves like the Visual Basic On Error Resume Next statement.

This is the sample from the documentation

var source = Rx.Observable.onErrorResumeNext(
  Rx.Observable.just(42),
  Rx.Observable.throw(new Error()),
  Rx.Observable.just(56),
  Rx.Observable.throw(new Error()),
  Rx.Observable.just(78)
);

var subscription = source.subscribe(
  data => console.log(data)
);
// => 42
// => 56
// => 78