Returning the 'last' row of each 'group by' in MySQL

This has worked for me thanks!

SELECT t1.* FROM foo t1
  JOIN (SELECT uid, MAX(id) id FROM foo GROUP BY uid) t2
    ON t1.id = t2.id AND t1.uid = t2.uid;

my version:

SELECT * FROM messages t1 JOIN (SELECT MAX(id) id FROM messages  where uid = 8279 and actv=1 GROUP BY uid ) t2 ON t1.id = t2.id ORDER BY datex desc LIMIT 0,10;

this code below doesn't return all rows I want because if max id column is an inactive one then it skips the group even if the group has active rows..

select * from messages where uid = 8279 and actv=1 and id In (Select max(id) From messages Group By uid) order by datex desc;

Returning the last row of each GROUP BY in MySQL with WHERE clause:

SELECT *
FROM foo
WHERE id IN (
  SELECT Max(id)
  FROM foo
  WHERE value='XYZ'
  GROUP BY u_id
)
LIMIT 0,30

if table is big in size. Make view containing all last row id

create view lastrecords as (select max(id) from foo where uid = a.uid group by uid)

Now join your main query with this view. It will be faster.

  SELECT t1.* FROM tablename as t1
    JOIN lastrecords as  t2
    ON t1.id = t2.id AND t1.uid = t2.uid;

OR You can do join with last records direct in query also:

SELECT t1.* FROM tablename as t1
JOIN (SELECT uid, MAX(id) id FROM tablename GROUP BY id) as  t2
ON t1.id = t2.id AND t1.uid = t2.uid;

Try this query -

SELECT t1.* FROM foo t1
  JOIN (SELECT uid, MAX(id) id FROM foo GROUP BY uid) t2
    ON t1.id = t2.id AND t1.uid = t2.uid;

Then use EXPLAIN to analyze queries.

---

SELECT t1.* FROM foo t1
  LEFT JOIN foo t2
    ON t1.id < t2.id AND t1.uid = t2.uid
WHERE t2.id is NULL;