Remove carriage return in Unix

I'm going to assume you mean carriage returns (CR, "\r", 0x0d) at the ends of lines rather than just blindly within a file (you may have them in the middle of strings for all I know). Using this test file with a CR at the end of the first line only:

$ cat infile
hello
goodbye

$ cat infile | od -c
0000000   h   e   l   l   o  \r  \n   g   o   o   d   b   y   e  \n
0000017

dos2unix is the way to go if it's installed on your system:

$ cat infile | dos2unix -U | od -c
0000000   h   e   l   l   o  \n   g   o   o   d   b   y   e  \n
0000016

If for some reason dos2unix is not available to you, then sed will do it:

$ cat infile | sed 's/\r$//' | od -c
0000000   h   e   l   l   o  \n   g   o   o   d   b   y   e  \n
0000016

If for some reason sed is not available to you, then ed will do it, in a complicated way:

$ echo ',s/\r\n/\n/
> w !cat
> Q' | ed infile 2>/dev/null | od -c
0000000   h   e   l   l   o  \n   g   o   o   d   b   y   e  \n
0000016

If you don't have any of those tools installed on your box, you've got bigger problems than trying to convert files :-)

Old School:

tr -d '\r' < filewithcarriagereturns > filewithoutcarriagereturns

The simplest way on Linux is, in my humble opinion,

sed -i.bak 's/\r$//g' <filename>

-i will edit the file in place, while the .bak will create a backup of the original file by making a copy of your file and adding the extension .bak at the end. (You can specify what ever you want after the -i, or specify only -i to not create a backup.)

The strong quotes around the substitution operator 's/\r//' are essential. Without them the shell will interpret \r as an escape+r and reduce it to a plain r, and remove all lower case r. That's why the answer given above in 2009 by Rob doesn't work.

And adding the /g modifier ensures that even multiple \r will be removed, and not only the first one.

tr -d '\r' < infile > outfile

See tr(1)