How to detect "empty" elements inside a tikz \foreach statement

The problem in the macro from the question:

\newcommand\Macro[1]{%
  \foreach \x in {#1} {
    \if\relax\detokenize{\x}\relax Empty!
    \else x=\x.
    \fi 
  }
}

is that \detokenize does not expand its argument and returns the two tokens \ and x. This is cured by adding an \expandafter:

\detokenize\expandafter{\x}

The full macro:

\newcommand\Macro[1]{%
  \foreach \x in {#1} {
    \if\relax\detokenize\expandafter{\x}\relax Empty!
    \else x=\x.
    \fi 
  }
}

Something like this?

\documentclass{article}
\usepackage{tikz}
\newcommand\Macro[1]{%
  \foreach \x in {#1} {
    \ifx\x\empty\relax Empty!
    \else x=\x.
    \fi 
  }
}
\begin{document}
\Macro{,,,4,5,5}
\end{document}

The mandatory expl3 answer (after noting that \detokenize\expandafter{\x} would be the solution):

\documentclass{article}
\usepackage{tikz}
\usepackage{xparse}

\ExplSyntaxOn
\NewExpandableDocumentCommand{\blankTF}{mmm}
 {% #1 = text to test, #2 = blank case, #3 = non blank case
  \str_if_eq_x:nnTF { #1 } { } { #2 } { #3 }
 }
\NewDocumentCommand{\lforeach}{O{,}mm}
 {% #1 = delimiter, #2 = list, #3 = code
  \seq_set_split:Nnn \l_andrew_foreach_seq { #1 } { #2 }
  \seq_map_inline:Nn \l_andrew_foreach_seq { #3 }
 }
\ExplSyntaxOff

\newcommand\Macro[1]{%
  \lforeach{#1}{%
    \blankTF{##1}{Empty!}{$|$##1$|$.}
  }
}

\begin{document}

\lforeach[-]{a-b--\texttt{c}}{%
    \blankTF{#1}{Empty!}{$|$#1$|$.}
  }

\lforeach{, ,,4, 5 ,5}{%
    \blankTF{#1}{Empty!}{$|$#1$|$.}
  }

\Macro{, ,,4, 5 ,5}

\end{document}

The current item in the cycle is denoted by #1 (which has to become ##1 in the definition of \Macro).