# H-Bridge with emitter followers

That is called an "H-Bridge."

It is often used to drive motors forwards as well as backwards.

In your case, it allows you to generate a magnetic field whose polarity and intensity you can vary using "control signal 1" and "control signal 2."

When both are high (or both are low,) no current flows through the coil.

If one is high and the other is low, then current will flow in a particular direction.

If you swap the high and lows, it will flow in the opposite direction.

Now, if you hold one steady and pulse the other you will get a pulsed current through the coil. It will be smoothed (somewhat) by the coil to a steady magnetic field whose strength is propotional to the duty cycle of the pulses.

Switching the polarity of the current also changes the polarity of the magnetic field.

That is very much a simplified description, but I think it contains enough key words that you should be able to locate more details on your own.

It is a common circuit with many uses - and plenty of tricks and traps that go into making, using, and controlling it.

A bit more on how it operates:

The key to the whole thing is how pnp and npn transistors function.

When the voltage on the base of an npn transistor is more than 0.7 volts above the voltage on the emitter, then current will flow through the collector to the emitter.

When the voltage on the base of a pnp transistor is more than 0.7 volts below the voltage on the collector, then current will flow through the collector to the emitter.

So, looking at the H-bridge, putting a high signal on one of the control signals will turn off the pnp and turn on the npn - that side of the bridge is connected to the positive supply voltage.

Now, if you put a low signal on the other control line the npn transistor will turn off and the pnp will turn on. That side of the bridge is connected to the ground.

Current can now flow from V+ on one side of the bridge, through the coils, to ground on the other side of the bridge.

So, which control signal is high and which is low dictates the direction of the current flow through the load in the middle of the bridge.

You also asked it is possible for both transistors on one side to turn on and cause a short circuit.

It can happen, and is called shoot through. Part of the design and operation of an H-bridge goes into making sure that it doesn't happen.

In the design you've posted, I don't think it can happen.

It looks to me like the transistors on each side can never be on at the same time. But, I'm not an engineer and may well have overseen something (though Tony is an engineer and doesn't think it can happen with this circuit.)

NO

The Vbe has a dead-zone for drive levels of < |+/-0.7V| however, back EMF during the time of load L/R=T(63%V) will occur where R is the DC resistance of coils.(DCR)

beware of the need to clamp inductive spikes to opposite rail with zener+diode pairs across motor or reverse Vce diodes across each transistor. In more advanced designs they use active clamps. Beware of reactive energy and current loop area in the layout. Keep it tight pairs from driver, power, ground to L to minimize CM noise.

However when commutating left right for forward and reverse. You must stop by having both top or bottom drivers high ( or low) to shunt the L/R =T time constant with another brake dead-time before direction reversal. This is done by your smart controller using Sig1=Sig2 = either 0 or 1. If this is not a motor, disregard.

When regulating current if the left side is high, right side is used for PWM average voltage to control surge current or velocity at steady state. THen when reversing load polarity, the opposite is done. Right side high and left side with ramped PWM towards full Vavg in the opposite polarity. If this is a motor, then the same is true for deaccelerating. Often a current shunt is used for current sensing, where the load inertia affects current during g time duration.

Also keep in mind these simple transistor switches have an hFE of about 10~5% of max hFE during saturation so input current and heat dissipation ought to be computed. while control signal ought to be above +12V or additional drop occurs due to Vbe. This is why MOSFETs are preferred but have shoot thru issues just like if these were open-collectors instead of emitter followers. THen the 2 inputs must be separated to 4 inputs with controlled dead-time.

This is the simplest bridge driver, but compromises Vdrop on each switch but ok for small bridges at 12V. Even though it may work at 5V, not recommended for poor efficiency.

On each side you have an NPN and a PNP transistor. If the control voltage levels are selected correctly, the NPN and PNP transistor will not be switched on at the same time.