You are given an integer array of size N. Increase all odd numbers contained in the array by the original value of the last odd number. If there are no odd numbers in the array, then leave the array unchanged. code example

Example 1: you are given an array of integers. your task is to print the sum of numbers that occurs for an even number of times in the array.

import collections
def fun(arr):
    mp = collections.defaultdict(int)
      
    for i in range(len(arr)):
        mp[arr[i]] += 1 
    sum = 0 
    for i in mp.keys(): 
          
        
        if (mp[i] % 2 == 0): 
            sum += i
    return sum
n= int(input())
arr = list(map(int,input().split()))
print(fun(arr))

Example 2: If there are an odd number of elements in the array, return the element in the middle of the array.

public String middleElement(String[] array)
{
    if (array.length >=1){
        if (array.length %2 != 0){
            return array[array.length/2];
        }
        else if(array.length %2 == 0){
            return array[array.length/2];
        }
        return "";
    }
    else return "";
}

Tags:

Misc Example