Why is `(True, True, True) == True, True, True` not True in Python?

This has to do with how expressions are evaluated in python.

In the first case, both a and b are tuples.

a = True, True, True
b = (True, True, True)


print(a == b)


<class 'tuple'>
<class 'tuple'>

So, they are compared as tuples and in-fact they are both equal in value.

But for case 2, it's evaluated left to right.

(True, True, True) == True, True, True

First the tuple (True, True, True) is compared with just True which is False.

Operator precedence. You're actually checking equality between (True, True, True) and True in your second code snippet, and then building a tuple with that result as the first item.

Recall that in Python by specifying a comma-separated "list" of items without any brackets, it returns a tuple:

>>> a = True, True, True
>>> print(type(a))
<class 'tuple'>
>>> print(a)
(True, True, True)

Code snippet 2 is no exception here. You're attempting to build a tuple using the same syntax, it just so happens that the first element is (True, True, True) == True, the second element is True, and the third element is True.

So code snippet 2 is equivalent to:

(((True, True, True) == True), True, True)

And since (True, True, True) == True is False (you're comparing a tuple of three objects to a boolean here), the first element becomes False.