When should we use intern method of String on String literals

On a recent project, some huge data structures were set up with data that was read in from a database (and hence not String constants/literals) but with a huge amount of duplication. It was a banking application, and things like the names of a modest set (maybe 100 or 200) corporations appeared all over the place. The data structures were already large, and if all those corp names had been unique objects they would have overflowed memory. Instead, all the data structures had references to the same 100 or 200 String objects, thus saving lots of space.

Another small advantage of interned Strings is that == can be used (successfully!) to compare Strings if all involved strings are guaranteed to be interned. Apart from the leaner syntax, this is also a performance enhancement. But as others have pointed out, doing this harbors a great risk of introducing programming errors, so this should be done only as a desparate measure of last resort.

The downside is that interning a String takes more time than simply throwing it on the heap, and that the space for interned Strings may be limited, depending on the Java implementation. It's best done when you're dealing with a known reasonable number of Strings with many duplications.


Java automatically interns String literals. This means that in many cases, the == operator appears to work for Strings in the same way that it does for ints or other primitive values.

Since interning is automatic for String literals, the intern() method is to be used on Strings constructed with new String()

Using your example:

String s1 = "Rakesh";
String s2 = "Rakesh";
String s3 = "Rakesh".intern();
String s4 = new String("Rakesh");
String s5 = new String("Rakesh").intern();

if ( s1 == s2 ){
    System.out.println("s1 and s2 are same");  // 1.
}

if ( s1 == s3 ){
    System.out.println("s1 and s3 are same" );  // 2.
}

if ( s1 == s4 ){
    System.out.println("s1 and s4 are same" );  // 3.
}

if ( s1 == s5 ){
    System.out.println("s1 and s5 are same" );  // 4.
}

will return:

s1 and s2 are same
s1 and s3 are same
s1 and s5 are same

In all the cases besides of s4 variable, a value for which was explicitly created using new operator and where intern method was not used on it's result, it is a single immutable instance that's being returned JVM's string constant pool.

Refer to JavaTechniques "String Equality and Interning" for more information.


I want to add my 2 cents on using == with interned strings.

The first thing String.equals does is this==object.

So although there is some miniscule performance gain ( you are not calling a method), from the maintainer point of view using == is a nightmare, because some interned strings have a tendency to become non-interned.

So I suggest not to rely on special case of == for interned strings, but always use equals as Gosling intended.

EDIT: interned becoming non-interned:

V1.0
public class MyClass
{
  private String reference_val;

  ...

  private boolean hasReferenceVal ( final String[] strings )
  {
    for ( String s : strings )
    {
      if ( s == reference_val )
      {
        return true;
      }
    }

    return false;
  }

  private void makeCall ( )
  {
     final String[] interned_strings =  { ... init with interned values ... };

     if ( hasReference( interned_strings ) )
     {
        ...
     }
  }
}

In version 2.0 maintainer decided to make hasReferenceVal public, without going into much detail that it expects an array of interned strings.

V2.0
public class MyClass
{
  private String reference_val;

  ...

  public boolean hasReferenceVal ( final String[] strings )
  {
    for ( String s : strings )
    {
      if ( s == reference_val )
      {
        return true;
      }
    }

    return false;
  }

  private void makeCall ( )
  {
     final String[] interned_strings =  { ... init with interned values ... };

     if ( hasReference( interned_strings ) )
     {
        ...
     }
  }
}

Now you have a bug, that may be very hard to find, because in majority of cases array contains literal values, and sometimes a non-literal string is used. If equals were used instead of == then hasReferenceVal would have still continue to work. Once again, performance gain is miniscule, but maintenance cost is high.


Learn Java String Intern - once for all

Strings in java are immutable objects by design. Therefore, two string objects even with same value will be different objects by default. However, if we wish to save memory, we could indicate to use same memory by a concept called string intern.

The below rules would help you understand the concept in clear terms:

  1. String class maintains an intern-pool which is initially empty. This pool must guarantee to contain string objects with only unique values.
  2. All string literals having same value must be considered same memory-location object because they have otherwise no notion of distinction. Therefore, all such literals with same value will make a single entry in the intern-pool and will refer to same memory location.
  3. Concatenation of two or more literals is also a literal. (Therefore rule #2 will be applicable for them)
  4. Each string created as object (i.e. by any other method except as literal) will have different memory locations and will not make any entry in the intern-pool
  5. Concatenation of literals with non-literals will make a non-literal. Thus, the resultant object will have a new memory location and will NOT make an entry in the intern-pool.
  6. Invoking intern method on a string object, either creates a new object that enters the intern-pool or return an existing object from the pool that has same value. The invocation on any object which is not in the intern-pool, does NOT move the object to the pool. It rather creates another object that enters the pool.

Example:

String s1=new String (“abc”);
String s2=new String (“abc”);
If (s1==s2)  //would return false  by rule #4
If (“abc” == “a”+”bc” )  //would return true by rules #2 and #3
If (“abc” == s1 )  //would return false  by rules #1,2 and #4
If (“abc” == s1.intern() )  //would return true  by rules #1,2,4 and #6
If ( s1 == s2.intern() )      //wound return false by rules #1,4, and #6

Note: The motivational cases for string intern are not discussed here. However, saving of memory will definitely be one of the primary objectives.