# Chemistry - What should the Rehm-Weller equation look like?

## Solution 1:

Both expressions are identical. It's just juggling of the signs, since

$$E^{\mathrm{red}}(D^{\cdot+}/D) = - E^{\mathrm{ox}}(D/D^{\cdot+})$$

Relevant primary references would be:

Rehm, D.; Weller, A. H.

*Isr. J. Chem.***1970**,*8*, 259-271.Rehm, D.; Weller, A. H.

*Ber. Bunsen-Ges. Phys. Chem.***1969**,*73*, 834-839.- Weller, A. H.
*Z. Phys. Chem. NF***1982**,*133*, 93-98.

A normative glossary of terms in photochemistry is available from the IUPAC.

## Solution 2:

By convention both donor (D) and acceptor (A) potentials are listed as reduction potentials. For a nice description, see Turro's explanation of the Rehm-Weller equation in his photochemical treatise "Modern Molecular Photochemistry of Organic Molecules"

To clarify, the equation that is being referenced is not actually the Rehm-Weller equation but is the "Gibbs free energy of photoinduced electron transfer".

Please refer to the IUPAC definition of Gibb's energy of photoinduced electron transfer.

The Gibbs energy of photoinduced electron transfer is part of the Rehm-Weller equation. The Rehm-Weller equation is the correlation between second order rate constants and Gibbs energy of photoinduced electron transfer.

See the IUPAC definition of the Rehm-Weller equation