What axioms are used to prove Godel's Incompleteness Theorems?

As Andres Caicedo points out in his comment (to the Question), the modest fragment $\sf{PRA}$ (Primitive Recursive Arithmetic) of $\sf{PA}$ (Peano arithmetic) is already is able to verify the incompleteness theorems.

Indeed, the proof of the Gödel-Rosser incompleteness proof is entirely syntactic and can be readily implemented in a fragment of $\sf{PRA}$ known as $I\Delta_0 + exp$, where $I\Delta_0$ is the weakening of $PA$ in which the induction scheme is only available for $\Delta_0$-formulas, and $exp$ asserts the totality of the exponential function $2^x$ (it is well-known that $I\Delta_0$ is unable to prove the totality of the exponential function).

It is worth noting that in the above $I\Delta_0 + exp$ can be even reduced to $I\Delta_0 + \Omega_1$, where $\Omega_1$ is the axiom asserting the totality of the function $2^{\left| x\right|^2 }$, where $\left| x\right|$ denotes the length of the binary expansion of $x$. The theory $I\Delta_0 + \Omega_1$ is commonly viewed as the weakest fragment of $\sf{PA}$ in which one can develop a workable "theory of syntax".

PS. As pointed out by Jeřábek, the incompleteness theorems can be implemented in even weaker systems.


You might already know this, but if you're looking for foundations of mathematics which are so weak that they don't prove the existence of non-r.e. sets, then you should study Simpson's book Subsystems of Second-Order Arithmetic, the "bible" of reverse mathematics. The weakest system in that book, RCA0, has as a model the recursive sets, and suffices for Goedel's first incompleteness theorem and even a weak version of Goedel's completeness theorem. More importantly, RCA0 suffices for a large amount of mathematics.

Simpson's book of course also investigates what can't be proved in RCA0. For example, Brouwer's fixed point theorem is unprovable in RCA0, roughly speaking because one can construct a continuous recursive map from the square into itself that has no recursive fixed point.


Here's a different way of looking at things. Use FPA to denote second-order Peano Arithmetic minus the Successor Axiom (the axiom which says that every natural number has a successor). FPA is neither weaker nor stronger than IΔ0+Ω1, since the latter assumes the Successor Axiom but assumes a weaker form of induction.

FPA can prove the First Incompleteness Theorem. Undoubtedly, fragments of FPA can as well.

More interesting is when one clarifies the nature of the logical system under metalogical study. Usually, the syntax of first-order logic is defined so that one can always concatenate two strings to form a larger one. E.g. one uses this principle in the Deduction Theorem, which is one of the first metalogical theorems one tends to prove. But this assumption, essentially equivalent to the Successor Axiom, is not necessary, and one can refrain from making it.

In this environment (where the syntax is not assumed to be unboundedly long), one can say this: FPA can prove the First Incompleteness Theorem. But Godel's proof seems only to work in the case of FPA + Successor Axiom. In the case FPA + not Successor Axiom, one basically formalizes the idea that a proof is generally longer than any axiom. It does not appear that Godel's proof of the Second Completeness Theorem goes through, and I do not know whether this can be repaired.