Using the reduce function to return an array

I know this is the same answer, but I just want to show that using reduce (), the syntax can also be reduced to a single line of code using ES6:

var store = [0,1,2,3,4];

var stored = store.reduce((pV,cV) => [...pV, cV], []);

console.log(stored);

reduce() can be useful if you need to return an array with multiple items for each item iterated:

var inputs = media.reduce((passedArray, video) => {
    passedArray.push("-i");
    passedArray.push(video.filepath);
    return passedArray;
}, []);

Here it's being used to build the input array for FFmpeg;

[{ name: "bob", filepath: "1.mp4" }, { name: "sue", filepath: "3.mp4" }]
=> ["-i", "1.mp4", "-i", "2.mp4]

Just for completeness, and for the next person who happens on this question, what you're doing is typically achieved with map which, as stated in the docs

map calls a provided callback function once for each element in an array, in order, and constructs a new array from the results

Contrast that with the description of reduce:

The reduce() method applies a function against an accumulator and each value of the array (from left-to-right) to reduce it to a single value.

(Emphasis mine) So you see, although you can manipulate reduce to return a new array, it's general usage is to reduce an array to a single value.

So for your code this would be:

var store = [0,1,2,3,4];

var stored = store.map(function(pV){
  console.log("pv: ", pV);
  return pV;
});

Much simpler than trying to reconstruct a new array using either push or concat within a reduce function.

push returns the new length of the array.

What you need is the initially provided array.

So change the code as below.

var store = [0, 1, 2, 3, 4];

var stored = store.reduce(function(pV, cV, cI){
  console.log("pv: ", pV);
  pV.push(cV);
  return pV; // *********  Important ******
}, []);

concat returns the new array combining the elements of the provided array and concatenated elements. so it works.