Using `select` command to print a menu in Bash

Your menu shown by select will look like:

1) apache
2) named
3) sendmail
Select an option and press Enter: 

At this time, you enter "1" or "2" or "3": you don't type the word.

Also, select will loop until it sees a break command, so you want this:

  case $opt in
        "apache")
          date
          break
          ;;
        "named")
          echo "test"
          break
          ;;
        "sendmail")
          echo "test 2"
          break
          ;;
        *) echo "invalid option";;
  esac

---

If you wanted to allow the user to enter either the number or the word, you could write this:

select opt in "${options[@]}"; do
  case "$opt,$REPLY" in
    apache,*|*,apache)     do_something; break ;;
    named,*|*,named)       do_something; break ;;
    sendmail,*|*,sendmail) do_something; break ;;
  esac
done

The comma has no syntactical significance, it's just there to be able to pattern match on either the $REPLY variable (which is what the user actually typed) or the $opt variable

Your $opt variable will be set to the option word corresponding to the number that the user inputs. If you want to look at what the user actually typed, look at $REPLY.