Typescript - Sort strings descending

A more current answer is that you can utilize String.prototype.localCompare() to get a numeric comparison value

Simple example:

let values = ["Saab", "Volvo", "BMW"];
values.sort((a, b) => b.localeCompare(a))

This also wont causes TypeScript warnings as the output of localCompare is a number

More info and additional function parameters can be seen here https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare

You need to create a comparison function and pass it as a parameter of sort function:

values.sort((one, two) => (one > two ? -1 : 1));

Use the following code to sorting the Array in ascending and descending order.

const ascending: any= values.sort((a,b) =>  (a > b ? 1 : -1));
const descending: any= values.sort((a,b) => (a > b ? -1 : 1))