Swift remove objects in Array range

Use removeSubrange method of array. Make a valid range by element location and length.

var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
let range = 1...3
array.removeSubrange(range)

print(array)

Output: [1, 5, 6, 7, 8, 9, 10]

Note: Range should be a valid range I mean it should not be out from array.

Here is yours way (by for loop) We can not remove objects by their indexes in a loop because every time object removes array's count and objects indexes will be change so out of range crash can come or you might get a wrong output. So you will have to take help of another array. See below example:-

var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
var newArray: [Int] = []
let minRange = 1
let maxRange = 3
for i in 0..<array.count {
     if i >= minRange && i <= maxRange {
        /// Avoid
        continue
     }

     newArray.append(array[i])
}

print(newArray)

Output: [1, 5, 6, 7, 8, 9, 10]

If you want to remove items by index in a range you have to inverse the indexes to start with the highest index otherwise you will get the out-of-range exception. Consider also that indexes are zero-based.

That's a safe version which checks also the upper bound of the array.

var array = [1, 2, 3, 4, 5, 6]
for i in (0...3).reversed() where i < array.count {
    array.remove(at: i)
}

print(array) // [5, 6]