Swift how to sort array of custom objects by property value

First, declare your Array as a typed array so that you can call methods when you iterate:

var images : [imageFile] = []

Then you can simply do:

Swift 2

images.sorted({ $0.fileID > $1.fileID })

Swift 3+

images.sorted(by: { $0.fileID > $1.fileID })

The example above gives desc sort order

[Updated for Swift 3 with sort(by:)] This, exploiting a trailing closure:

images.sorted { $0.fileID < $1.fileID }

where you use < or > depending on ASC or DESC, respectively. If you want to modify the images array, then use the following:

images.sort { $0.fileID < $1.fileID }

If you are going to do this repeatedly and prefer to define a function, one way is:

func sorterForFileIDASC(this:imageFile, that:imageFile) -> Bool {
  return this.fileID > that.fileID
}

and then use as:

images.sort(by: sorterForFileIDASC)

Nearly everyone gives how directly, let me show the evolvement:

you can use the instance methods of Array:

// general form of closure
images.sortInPlace({ (image1: imageFile, image2: imageFile) -> Bool in return image1.fileID > image2.fileID })

// types of closure's parameters and return value can be inferred by Swift, so they are omitted along with the return arrow (->)
images.sortInPlace({ image1, image2 in return image1.fileID > image2.fileID })

// Single-expression closures can implicitly return the result of their single expression by omitting the "return" keyword
images.sortInPlace({ image1, image2 in image1.fileID > image2.fileID })

// closure's argument list along with "in" keyword can be omitted, $0, $1, $2, and so on are used to refer the closure's first, second, third arguments and so on
images.sortInPlace({ $0.fileID > $1.fileID })

// the simplification of the closure is the same
images = images.sort({ (image1: imageFile, image2: imageFile) -> Bool in return image1.fileID > image2.fileID })
images = images.sort({ image1, image2 in return image1.fileID > image2.fileID })
images = images.sort({ image1, image2 in image1.fileID > image2.fileID })
images = images.sort({ $0.fileID > $1.fileID })

For elaborate explanation about the working principle of sort, see The Sorted Function.