SQL query to check if a name begins and ends with a vowel

in Microsoft SQL server you can achieve this from below query:

SELECT distinct City FROM STATION WHERE City LIKE '[AEIOU]%[AEIOU]'

Or

SELECT distinct City FROM STATION WHERE City LIKE '[A,E,I,O,U]%[A,E,I,O,U]'

Update --Added Oracle Query

--Way 1 --It should work in all Oracle versions

SELECT DISTINCT CITY FROM STATION WHERE REGEXP_LIKE(LOWER(CITY), '^[aeiou]') and  REGEXP_LIKE(LOWER(CITY), '[aeiou]$');

--Way 2 --it may fail in some versions of Oracle

SELECT DISTINCT CITY FROM STATION WHERE REGEXP_LIKE(LOWER(CITY), '^[aeiou].*[aeiou]');

--Way 3 --it may fail in some versions of Oracle

SELECT DISTINCT CITY FROM STATION WHERE REGEXP_LIKE(CITY, '^[aeiou].*[aeiou]', 'i');

You could use a regular expression:

SELECT DISTINCT city
FROM   station
WHERE  city RLIKE '^[aeiouAEIOU].*[aeiouAEIOU]$'

You can try one simple solution for MySQL:

SELECT DISTINCT city FROM station WHERE city REGEXP "^[aeiou].*[aeiou]$";

Use a regular expression.

WHERE name REGEXP '^[aeiou].*[aeiou]$'

^ and $ anchor the match to the beginning and end of the value.

In my test, this won't use an index on the name column, so it will need to perform a full scan, as would

WHERE name LIKE 'a%a' OR name LIKE 'a%e' ...

I think to make it use an index you'd need to use a union of queries that each test the first letter.

SELECT * FROM table
WHERE name LIKE 'a%' AND name REGEXP '[aeiou]$'
UNION
SELECT * FROM table
WHERE name LIKE 'e%' AND name REGEXP '[aeiou]$'
UNION
SELECT * FROM table
WHERE name LIKE 'i%' AND name REGEXP '[aeiou]$'
UNION
SELECT * FROM table
WHERE name LIKE 'o%' AND name REGEXP '[aeiou]$'
UNION
SELECT * FROM table
WHERE name LIKE 'u%' AND name REGEXP '[aeiou]$'