sort dictionary based on key code example

Example 1: how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Example 2: sort dictionary by key

sortedDictionary = sorted(mydictionary.keys())

Example 3: sort dict of dicts by key

channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'}, 
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'}, 
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'}, 
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'}, 
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'}, 
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'}, 
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}

channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
    print(key, ':', value)