Sort array by month and year

You need change the string to new Date(dateString) format like

new Date(Month Date Year)

Updated regex Pattern for Both Array

https://regex101.com/r/h1cm1z/2/

Updated Sort Second array based on first array sorting index

var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
var arr2 =['55','2','3','0','21','132'];

function datesort(arr){
 return arr.concat().sort((a,b)=>{
 a = a.replace(/(\d+)(.*)/g,' 1 $1'); // Month 1 YEAR
 b = b.replace(/(\d+)(.*)/g,' 1 $1'); // Month 1 YEAR
  return new Date(a) - new Date(b)
})
}

var after_arr1 =new datesort(arr1);
var after_arr2 = arr1.reduce(function(a,b,c){
     var ind = after_arr1.indexOf(b);
     a[ind] = arr2[c]
     return a
},[]);


console.log(after_arr1.join(','));
console.log(after_arr2.join(','))


You could get the date as a sortable string and sort it.

For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.

The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the function the string is destructed into month and year parts, and replaced by its ISO 8601 representation. The replacement function callback takes the matched items, returns an array with a formatted year and the month of an object with the month names and the related month numbers. Then, this array is joined and returned.

Sorting takes place with a comparison with String#localeCompare.

var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
    array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
    array3 = ['55', '2', '3', '0', '21', '132'],
    indices = Object
        .keys(array1)
        .sort(function (a, b) {
            function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                    s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
            }
            return getD(a).localeCompare(getD(b));
        }),
    result = [array1, array3].map(a => indices.map(i => a[i]));
  
result.forEach(a => console.log(...a));


const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

//const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
//Can be done easily by using momentjs, darte-fns, but here i will do it natively

const t = {
  Jan: 1,
  Feb: 2,
  Mar: 3,
  Apr: 4,
  May: 5,
  Jun: 6,
  Jul: 7,
  Aug: 8,
  Sep: 9,
  Oct: 10,
  Nov: 11,
  Dec: 12
}
const giveConcatString = (a, t) => {
  const monthPart = a.substr(0, 3)
  const yearPart = a.substr(3)
  return `${yearPart}${t[monthPart]}`
}
const sortedArray = input.sort((a, b) => {
  const concatString = giveConcatString(a, t)
  const concatStringB = giveConcatString(b, t)
  return concatString <= concatStringB ? -1 : 1

})
console.log(sortedArray)

This may help you solve this problem. Did it natively.