Skip first element of an array in Golang

Yes. Use this

for _, val := range Arr[1:] {
// something to do with val
}

Or in case you can get empty slice:

for i := 1; i < len(Arr); i++ {
// something to do with Arr[i]
}

Use a standard for loop or the slice operator:

for _, val := range Arr[1:] {
    // Do something
}

// Or
for i := 1; i < len(Arr); i++ {
    val = Arr[i]
    // Do something
}

convert to slice then skip first element(with the range query):

package main

import "fmt"

func main() {
    Arr := [...]int{1, 2, 3, 4}
    for _, val := range Arr[1:] {
        fmt.Println(val)
    }
}

using index to skip first element(with the range query):

package main

import "fmt"

func main() {
    Arr := [...]int{1, 2, 3, 4}
    for i, val := range Arr {
        if i == 0 {
            continue
        }
        fmt.Println(val)
    }
}

using one bool var to skip first element(with the range query):

package main

import "fmt"

func main() {
    Arr := [...]int{1, 2, 3, 4}
    first := true
    for _, val := range Arr {
        if first {
            first = false
            continue
        }
        fmt.Println(val)
    }
}