Size Does Matter (at least referring to bottles)

Python 2, 61 60 59 bytes

lambda n:[a*(1+.03*n)**i*75for a in 4,8for i in range(n/2)]

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_{-1 byte, thanks to Joseph Sible}

Wolfram Language (Mathematica), 36 bytes

{#,2#}&[300(1+.03#)^Range[0,#/2-1]]&

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05AB1E, 15 bytes

₆v;F.03*>NmyтP,

Port of @TFeld's Python 2 answer, so make sure to upvote him.

Try it online or verify all test cases.

Explanation:

₆                # Push builtin integer 36
 v               # Loop `y` over both digits:
  ;              #  Halve the (implicit) input-integer
   F             #  Inner loop `N` in the range [0, input/2):
    .03*         #   Multiply the (implicit) input by 0.03
                 #   (alternative 4-byter: `т/3*` # divide by 100, multiply by 3)
        >        #   Increase this by 1
         Nm      #   Take it to the power `N`
           yт    #   Push both `y` and 100
             P   #   And take the product of the entire stack
              ,  #   Then pop and print this number with trailing newline