Show all duplicated rows

You've found your duplicated records but you're interested in getting all the information attached to them. You need to join your duplicates to your main table to get that information.

select *
  from my_table a
  join ( select firstname, lastname 
           from my_table 
          group by firstname, lastname 
         having count(*) > 1 ) b
    on a.firstname = b.firstname
   and a.lastname = b.lastname

This is the same as an inner join and means that for every record in your sub-query, that found the duplicate records you find everything from your main table that has the same firstseen and lastseen combination.

You can also do this with in, though you should test the difference:

select *
  from my_table a
 where ( firstname, lastname ) in   
       ( select firstname, lastname 
           from my_table 
          group by firstname, lastname 
         having count(*) > 1 )

Further Reading:

• A visual representation of joins from Coding Horror
• Join explanation from Wikipedia

SELECT DISTINCT t1.*
FROM myTable AS t1
INNER JOIN myTable AS t2
  ON t1.firstname = t2.firstname
  AND t1.lastname = t2.lastname
  AND t1.objid <> t2.objid

This will output every row which has a duplicate, basing on firstname and lastname.

Here's a little more legible way to do Ben's first answer:

WITH duplicates AS (
   select    firstname, lastname
   from      my_table
   group by  firstname, lastname
   having    count(*) > 1
)
SELECT    a.*
FROM      my_table   a
JOIN      duplicates b ON (a.firstname = b.firstname and a.lastname = b.lastname)