Shortest Solution in Python 3 for Caught Speeding - CodingBat

Python 3, 32 bytes

lambda a,b:(a-b*5>60)+(a-b*5>80)

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Python 3, 50 bytes

If io must be done with stdin and stdout

s=int(input())-5*int(input());print((s>60)+(s>80))

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Python 3, 51 45 bytes

lambda a,b:min(2,max(0,(a//1-5*b//1-41)//20))

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I was able to shave 6 bytes from your approach by using everyone's favourite python golfing keyword: lambda.

This turns your program into an anonymous function, which then can be called in the footer of a program.

Edit: I know that this question is way old, but I only just recently thought of using //1 to convert things to an integer instead of using int(...).