Shortcut to generate an NSRange for entire length of NSString?

Function? Category method?

- (NSRange)fullRange
{
    return (NSRange){0, [self length]};
}

---

[myString replaceOccurrencesOfString:@"replace_me"
                          withString:replacementString
                             options:NSCaseInsensitiveSearch
                               range:[myString fullRange]];

Swift 4+, useful for NSRegularExpression and NSAttributedString

extension String {
    var nsRange : NSRange {
        return NSRange(self.startIndex..., in: self)
    }

    func range(from nsRange: NSRange) -> Range<String.Index>? {
        return Range(nsRange, in: self)
    }
}

Not that I know of. But you could easily add an NSString category:

@interface NSString (MyRangeExtensions)
- (NSRange)fullRange
@end

@implementation NSString (MyRangeExtensions)
- (NSRange)fullRange {
  return (NSRange){0, self.length};
}

Swift

NSMakeRange(0, str.length)

or as an extension:

extension NSString {
    func fullrange() -> NSRange {
        return NSMakeRange(0, self.length)
    }
}