Sed to print out the line number

AWK:

awk 'NR==2,NR==4{print NR" "$0}' file.txt

Double sed:

sed '2,4!d;=' file.txt | sed 'N;s/\n/ /'

glen jackmann's sed and paste:

sed '2,4!d;=' file.txt | paste -d: - -

Perl:

perl -ne 'print "$. $_" if ($.>=2 and $.<=4)' file.txt

Equivalent Perl:

perl -ne 'print "$. $_" if $.==2..$.==4' file.txt

cat and sed:

cat -n file.txt | sed -n '2,4p'

Also see this answer to a similar question.

A bit of explanation:

sed -n '2,4p' and sed '2,4!d;=' do the same thing: the first only prints lines between the second and the fourth (inclusive), the latter "deletes" every line except those.
sed = prints the line number followed by a newline. See the manual.
cat -n in the last example can be replaced by nl or grep -n ''.

I have done by below mentioned 2 methods

Method1

awk '/2/{x=NR+2}(NR<=x){print NR"-"$0 }' filename

command

2-Line 2
3-Line 3
4-Line 4

Method2

sed -n '{;=;p}' filename| sed "N;s/\n/ /g"| sed -n '/2/,+2p'

output

2 Line 2
3 Line 3
4 Line 4

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