Scrapy, only follow internal URLS but extract all links found

An updated code based on 12Ryan12's answer,

from scrapy.spiders import CrawlSpider, Rule
from scrapy.linkextractors.lxmlhtml import LxmlLinkExtractor
from scrapy.item import Item, Field

class MyItem(Item):
    url= Field()


class someSpider(CrawlSpider):
    name = 'crawltest'
    allowed_domains = ['someurl.com']
    start_urls = ['http://www.someurl.com/']
    rules = (Rule(LxmlLinkExtractor(allow=()), callback='parse_obj', follow=True),)

    def parse_obj(self,response):
        item = MyItem()
        item['url'] = []
        for link in LxmlLinkExtractor(allow=(),deny = self.allowed_domains).extract_links(response):
            item['url'].append(link.url)
        return item

You can also use the link extractor to pull all the links once you are parsing each page.

The link extractor will filter the links for you. In this example the link extractor will deny links in the allowed domain so it only gets outside links.

from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors import LxmlLinkExtractor
from myproject.items import someItem

class someSpider(CrawlSpider):
  name = 'crawltest'
  allowed_domains = ['someurl.com']
  start_urls = ['http://www.someurl.com/']

  rules = (Rule(LxmlLinkExtractor(allow=()), callback='parse_obj', follow=True),)


  def parse_obj(self,response):
    for link in LxmlLinkExtractor(allow=(),deny = self.allowed_domains).extract_links(response):
        item = someItem()
        item['url'] = link.url

A solution would be make usage a process_link function in the SgmlLinkExtractor Documentation here http://doc.scrapy.org/en/latest/topics/link-extractors.html

class testSpider(CrawlSpider):
    name = "test"
    bot_name = 'test'
    allowed_domains = ["news.google.com"]
    start_urls = ["https://news.google.com/"]
    rules = (
    Rule(SgmlLinkExtractor(allow_domains=()), callback='parse_items',process_links="filter_links",follow= True) ,
     )

    def filter_links(self, links):
        for link in links:
            if self.allowed_domains[0] not in link.url:
                print link.url

        return links

    def parse_items(self, response):
        ### ...