Removing apostrophe from all file names

You could try something like this (bash):

shopt -s nullglob
for i in *\'* ; do mv -v "$i" "${i/\'/}" ; done

This uses shell string replacement. You probably don't want to glob files that don't have ' in them since the mv would fail. Without the nullglob option, the glob pattern itself would be passed to mv if there are no matching files.

Always put double quotes around variable substitutions $foo and command substitutions $(foo) (unless you know why you need to leave them out and why it's ok to do so).

for i in *; do mv "$i" "$(echo "$i" | tr -d "'")"; done

This will mostly work, with a few restrictions:

  • You'll get bad behavior or errors if a file name begins with -, because mv will interpret it as an option.
  • This does not affect files whose name begins with ..
  • With some setups, this will mangle backslashes in the echo command.
  • Newlines at the end of the name are lost.

In ksh93, bash and zsh, you can write this with less hassle using the ${VARIABLE//PATTERN/REPLACEMENT} construct. Adding -- to mv takes care of file names beginning with -. If you have file names beginning with ., add .* or .[^.]* ..?* after * as needed.

for i in *; do mv -- "$i" "${i//\'/}"; done

In zsh, you can use zmv:

zmv '(*)' "\${1//\\'/}"

Under Debian, Ubuntu and other derivatives, you can use the rename Perl script.

rename "s/'//g" *

I assume your problem is the file also had spaces in its name. I can't reproduce your error without it.

$ touch "file" "user's file"
$ for i in *; do mv $i `echo $i | tr -d "'"`; done
mv: `file1' and `file1' are the same file
mv: target `file' is not a directory

So the reason it's failing is the second message: target 'file' is not a directory.

When your for loop sees a file with a space, it runs this:

mv user's file users file

So it thinks you're specifying three files (user's, file, and users), and a directory to move those files into (file).

Proper quoting of both should solve your immediate problem

$ for i in ./*; do mv "$i" "$(echo "$i" | tr -d "'")"; done