Register every table/class from an app in the Django admin page

Seems get_models and get_app are no longer available in django 1.8.

The following can be used:

from django.contrib import admin
from django.apps import apps

app = apps.get_app_config('dashboard')

for model_name, model in app.models.items():
    admin.site.register(model)

EXTENSION: If you would like to show all or select fields of the model as a grid instead of a single column unicode representation of the model objects you may use this:

app = apps.get_app_config('your_app_name')
for model_name, model in app.models.items():
    model_admin = type(model_name + "Admin", (admin.ModelAdmin,), {})

    model_admin.list_display = model.admin_list_display if hasattr(model, 'admin_list_display') else tuple([field.name for field in model._meta.fields])
    model_admin.list_filter = model.admin_list_filter if hasattr(model, 'admin_list_filter') else model_admin.list_display
    model_admin.list_display_links = model.admin_list_display_links if hasattr(model, 'admin_list_display_links') else ()
    model_admin.list_editable = model.admin_list_editable if hasattr(model, 'admin_list_editable') else ()
    model_admin.search_fields = model.admin_search_fields if hasattr(model, 'admin_search_fields') else ()

    admin.site.register(model, model_admin)

What this does is, it extends ModelAdmin class on the fly and sets the list_display field which is required for showing model data in grid representation in the admin. If you list your desired fields in your model as admin_list_display it takes that one, or generates a tuple of all fields available in the model, otherwise.

Other optional fields can similarly be set, such as list_filter.

See django documentation for more info on list_display.

From Django 1.7 on, you can use this code in your admin.py:

from django.apps import apps
from django.contrib import admin
from django.contrib.admin.sites import AlreadyRegistered

app_models = apps.get_app_config('my_app').get_models()
for model in app_models:
    try:
        admin.site.register(model)
    except AlreadyRegistered:
        pass

From Django 1.8, to fix the error message

RemovedInDjango19Warning: django.db.models.get_app is deprecated.

We can use this approach in 2 lines

from django.contrib import admin
from my_app.models import *
from django.apps import apps

for model in apps.get_app_config('my_app').models.values():
    admin.site.register(model)

I figured it out with @arie's link (for django < 1.8):

from django.contrib import admin
from django.db.models import get_models, get_app

for model in get_models(get_app('doors')):
    admin.site.register(model)

But I wonder if I can do this without get_app... Couldn't the code be smart enough to know the name of its own app?