Regex to match 2 digits, optional decimal, two digits

EDIT: Changed to fit other feedback.

I understood you to mean that if there is no decimal point, then there shouldn't be two more digits. So this should be it:

\d{0,2}(\.\d{1,2})?

That should do the trick in most implementations. If not, you can use:

[0-9]?[0-9]?(\.[0-9][0-9]?)?

And that should work on every implementation I've seen.

You mentioned that you want the regex to match each of those strings, yet you previously mention that the is 1-2 digits before the decimal?

This will match 1-2 digits followed by a possible decimal, followed by another 1-2 digits but FAIL on your example of .33

\d{1,2}\.?\d{1,2}

This will match 0-2 digits followed by a possible deciaml, followed by another 1-2 digits and match on your example of .33

\d{0,2}\.?\d{1,2}

Not sure exactly which one you're looking for.

(?<![\d.])(\d{1,2}|\d{0,2}\.\d{1,2})?(?![\d.])

Matches:

Does not match:

To build on Lee's answer, you need to anchor the expression to satisfy the requirement of not having more than 2 numbers before the decimal.

If each number is a separate string, you can use the string anchors:

^\d{0,2}(\.\d{1,2})?$

If each number is within a string, you can use the word anchors:

\b\d{0,2}(\.\d{1,2})?\b

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