Regex - finding capital words in string

The last letter of the match is in group because of inner parentheses. Just drop those and you'll be fine.

>>> t = re.findall('([A-Z][a-z]+)', line)
>>> t
['Cow', 'Apple', 'Woof']
>>> t = re.findall('([A-Z]([a-z])+)', line)
>>> t
[('Cow', 'w'), ('Apple', 'e'), ('Woof', 'f')]

The count of capitalised words is, of course, len(t).

I use the findall function to find all instances that match the regex. The use len to see how many matches there are, in this case, it prints out 3. You can check if the length is greater than 2 and return a True or False.

import re

line = 'Cow Apple think Woof'

test = re.findall(r'(\b[A-Z]([a-z])*\b)',line)
print(len(test) >= 2)

If you want to use only regex, you can search for a capitalized word then some characters in between and another capitalized word.

test = re.search(r'(\b[A-Z][a-z]*\b)(.*)(\b[A-Z][a-z]*\b)',line)
print(bool(test))

• (\b[A-Z][a-z]*\b) - finds a capitalized word
• (.*) - matches 0 or more characters
• (\b[A-Z][a-z]*\b) - finds the second capitalized word

This method isn't as dynamical since it will not work for trying to match 3 capitalized word.

import re

sent = "His email is [email protected], however his wife uses [email protected]"

x = re.findall('[A-Za-z]+@[A-Za-z\.]+', sent)

print(x)

If there is a period at the end of an email ID (abc@some,com.), it will be returned at the end of the email address. However, this can be dealt separately.