Regex find comma not inside quotes
Stand back and be amazed!
Here is the regex you seek:
(?!\B"[^"]*),(?![^"]*"\B)
Here is a demonstration:
regex101 demo
- It does not match the second line because the
"you inserted does not have a closing quotation mark. - It will not match values like so:
,r"a string",10because the letter on the edge of the"will create a word boundary, rather than a non-word boundary.
Alternative version
(".*?,.*?"|.*?(?:,|$))
This will match the content and the commas and is compatible with values that are full of punctuation marks
regex101 demo
The below regex is for parsing each fields in a line, not an entire line
Apply the methodical and desperate regex technique: Divide and conquer
Case: field does not contain a quote
- abc,
- abc(end of line)
[^,"]*(,|$)
Case: field contains exactly two quotes
- abc"abc,"abc,
- abc"abc,"abc(end of line)
[^,"]*"[^"]*"[^,"]*(,|$)
Case: field contains exactly one quote
- abc"abc(end of line)
- abc"abc, (and that there's no quote before the end of this line)
[^,"]*"[^,"]$
[^,"]*"[^"],(?!.*")
Now that we have all the cases, we then '|' everything together and enjoy the resultant monstrosity.