Redirect User From Browser to My App after open a specific URL

1. open the firebase app
2. click on a dynamic link
3. create your own redirect call back link on firebase like https://example.page.link/payment

4. setup link on your manifest.xml file like following code

<intent-filter android:label="@string/app_name" android:autoVerify="true">
           <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
               <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="https"
                    android:host="example.page.link" android:path="/payment"/>
                <data android:scheme="http"
                    android:host="example.page.link" android:path="/payment"/>
    </intent-filter>

5. run your app
6. check the firebase link on android phone browser
7. it's work yup

Try to open it like myapp://returnApp/?status=1 (add trailing slash character). This is happens because path parameter is defined with default value of /.

Unfortunately, you can't match exactly for empty string. As documentation states:

The path part of a URI which must begin with a /.

If you are really need to start app with exactly url myapp://returnApp?status=1 you can add android:pathPattern=".*" parameter to your data clause like

<intent-filter>
    ...
    <data android:host="returnApp" android:scheme="myapp" android:pathPattern=".*"></data>
</intent-filter>

Intent filter with data android:pathPattern=".*" will match for any paths including empty one.