Python Selenium - get href value

As per the given HTML:

<p class="sc-eYdvao kvdWiq">
    <a href="https://www.iproperty.com.my/property/setia-eco-park/sale-1653165/">Shah Alam Setia Eco Park, Setia Eco Park</a>
</p>

As the href attribute is within the <a> tag ideally you need to move deeper till the <a> node. So to extract the value of the href attribute you can use either of the following Locator Strategies:

  • Using css_selector:

    print(driver.find_element_by_css_selector("p.sc-eYdvao.kvdWiq > a").get_attribute('href'))

  • Using xpath:

    print(driver.find_element_by_xpath("//p[@class='sc-eYdvao kvdWiq']/a").get_attribute('href'))

If you want to extract all the values of the href attribute you need to use find_elements* instead:

  • Using css_selector:

    print([my_elem.get_attribute("href") for my_elem in driver.find_elements_by_css_selector("p.sc-eYdvao.kvdWiq > a")])

  • Using xpath:

    print([my_elem.get_attribute("href") for my_elem in driver.find_elements_by_xpath("//p[@class='sc-eYdvao kvdWiq']/a")])

Dynamic elements

However, if you observe the values of class attributes i.e. sc-eYdvao and kvdWiq ideally those are dynamic values. So to extract the href attribute you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

  • Using CSS_SELECTOR:

    print(WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "p.sc-eYdvao.kvdWiq > a"))).get_attribute('href'))

  • Using XPATH:

    print(WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, "//p[@class='sc-eYdvao kvdWiq']/a"))).get_attribute('href'))

If you want to extract all the values of the href attribute you can use visibility_of_all_elements_located() instead:

  • Using CSS_SELECTOR:

    print([my_elem.get_attribute("innerHTML") for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "p.sc-eYdvao.kvdWiq > a")))])

  • Using XPATH:

    print([my_elem.get_attribute("innerHTML") for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//p[@class='sc-eYdvao kvdWiq']/a")))])

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait     
from selenium.webdriver.common.by import By     
from selenium.webdriver.support import expected_conditions as EC

You want driver.find_elements if more than one element. This will return a list. For the css selector you want to ensure you are selecting for those classes that have a child href

elems = driver.find_elements_by_css_selector(".sc-eYdvao.kvdWiq [href]")
links = [elem.get_attribute('href') for elem in elems]

You might also need a wait condition for presence of all elements located by css selector.

elems = WebDriverWait(driver,10).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, ".sc-eYdvao.kvdWiq [href]")))

Tags:

Python

Xpath

Css Selectors

Selenium

Webdriverwait

Recent Posts