Python equivalent of Scala case class

The current, modern way to do this (as of Python 3.7) is with a data class. For example, the Scala case class Point(x: Int, y: Int) becomes:

from dataclasses import dataclass

@dataclass(frozen=True)
class Point:
    x: int
    y: int

The frozen=True part is optional; you can omit it to get a mutable data class. I've included it for parity with Scala's case class.

Before Python 3.7, there's collections.namedtuple:

from collections import namedtuple
Point = namedtuple('Point', ['x', 'y'])

Namedtuples are immutable, as they are tuples. If you want to add methods, you can extend the namedtuple:

class Point(namedtuple('Point', ['x', 'y'])):
    def foo():
        pass

If you use python3.7 you get data classes as @dataclass. Official doc here - 30.6. dataclasses — Data Classes

from dataclasses import dataclass

@dataclass
class CustomerOrder:
  order_id: int
  customer_id: str
  item_name: str

order = CustomerOrder(1, '001', 'Guitar')
print(order)

Make sure to upgrade python3 to python 3.7 or if you use python 3.6 install dataclass from pypi

In macos: brew upgrade python3

While above data class in scala looks like,

scala> final case class CustomerOrder(id: Int, customerID: String, itemName: String)
defined class CustomerOrder