python 2.7 equivalent of built-in method int.from_bytes

Use the struct module to unpack your bytes into integers.

import struct
>>> struct.unpack("<L", "y\xcc\xa6\xbb")[0]
3148270713L

You can treat it as an encoding (Python 2 specific):

>>> int('f483'.encode('hex'), 16)
1714698291

Or in Python 2 and Python 3:

>>> int(codecs.encode(b'f483', 'hex'), 16)
1714698291

The advantage is the string is not limited to a specific size assumption. The disadvantage is it is unsigned.

struct.unpack(">i","f483")[0]

maybe?

> means big-endian and i means signed 32 bit int

see also: https://docs.python.org/2/library/struct.html

> import binascii

> barray = bytearray([0xAB, 0xCD, 0xEF])
> n = int(binascii.hexlify(barray), 16)
> print("0x%02X" % n)

0xABCDEF

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