# Print this maximally long URL

## Python 3, 86 $$\\cdots\$$ 81 77 bytes

Saved 3 bytes thanks to mypetlion!!!
Saved 4 bytes thanks to Shieru Asakoto!!!

print(f"http://{'.'.join(chr(i+97)*int(1+.7**-i/120)for i in range(26))}.me")


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Uses Shieru Asakoto's 0-based formula.

## APL (Dyalog), 41 38 bytes

-3 bytes thanks to Bubbler

2⌽'mehttp://',∊'.',¨⍨⎕A⍴¨⍨⌊1+62×.7*⍒⎕A


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Outputs the URL with the letters capitalised. Uses the 0 indexed formula $$\ \lfloor 1 + 62 \times 0.7^{25-x} \rfloor \$$, since $$\ (\frac{10}{7})^{x-25} = ((\frac{7}{10})^{-1})^{x-25} = (\frac{7}{10})^{25-x}\$$

### Explanation:

2⌽                         ⍝ Rotate by two places (moving the 'me' to the end)
'mehttp://'              ⍝ The start string
,             ⍝ Followed by
∊               ⍝ The flattened string of
'.'            ⍝ A period
,⍨¨         ⍝ Appended to the end of each of
⎕A            ⍝ The uppercase alphabet
⍴¨⍨         ⍝ Where each letter is repeated by
⌊               ⍝ The floor of
1+             ⍝ 1 plus
62×          ⍝ 62 times
.7*       ⍝ 0.7 to the power of
⍒⎕A  ⍝ The range 26 to 1


## 05AB1E, 252423 21 bytes

žXAS.7Ƶ-t∞-m>×….me¬ýJ


-1 byte thanks to @Neil's analysis that *(10/7)** is the same as /.7**.
-3 bytes thanks to @Grimmy using a different formula and ingenious use of ý!

Try it online.

Explanation:

The formula used to get the correct amount of characters of the alphabet, where $$\n\$$ is the 1-based index of the alphabetic letter:
$$\a(n) = \left\lfloor0.7^{(\sqrt{208}-n)}+1\right\rfloor\$$

žX                     # Push builtin "http://"
Ƶ-               # Push compressed 208
t              # Take the square-root of that: 14.422...
∞             # Push an infinite list of positive integers: [1,2,3,...]
-            # Subtract each from the 14.422...: [13.442...,12.442...,...]
.7     m           # Take 0.7 to the power of each of these: [0.008...,0.011...,...]
>          # Increase each by 1: [1.008...,1.011...,...]
AS                   # Push the lowercase alphabet as list of characters,
×         # and repeat each the calculated values amount of times as string
# (which implicitly truncates the floats to integers, and ignores
#  the floats beyond the length of the alphabet)
….me     # Push ".me"
¬    # Push its head (the "."), without popping the ".me" itself
ý   # Join with delimiter. Normally it will use the top value as
# delimiter and joins the top-1'th list. In this case however, the
# top-1'th item is a string, so instead it will join the entire stack
# together. BUT, because the stack contains a list, it will instead
# only join all lists on the stacks by the "." delimiter
J  # And finally join the three strings on the stack together
# (after which this result is output implicitly)


See this 05AB1E tip of mine (section How to compress large integers?) to understand why Ƶ- is 208.