Pandas Finding Index From Values In Column

Use boolean indexing:

df.index[df.Column == 17]

If need excluding row 0:

df1 = df.iloc[1:]
df1.index[df1.Column == 17]

Sample:

df = pd.DataFrame({'Column': {'Item 1': 0, 'Item 2': 20, 'Item 5': 12, 'Item 3': 34, 'Item 7': 17}})
print (df)
       Column
Item 1       0
Item 2      20
Item 3      34
Item 5      12
Item 7      17

print (df.index[df.Column == 17])
Index(['Item 7'], dtype='object')

print (df.index[df.Column == 17].tolist())
['Item 7']

df1 = df.iloc[1:]
print (df1)
        Column
Item 2      20
Item 3      34
Item 5      12
Item 7      17

print (df1.index[df1.Column == 17].tolist())
['Item 7']

I tried one of the methods above and it did not work for me. I then put a bit more thought into it and realized I was making it more complicated than it needed to be. Here's the method I am using in my own program to get this functionality:

x = 17
df = pandas.DataFrame({'Item':[1,2,3,150],'Column':[0,20,34,17]})
response = df[df['Column'] == x].iloc[0]['Item']

print(response)

Output:

150