Mongoose greater than and equal

Query.prototype.gt method is the same as using "greater than" operator.

In your case, you have to use gte method that returns exactly what you need - results that are greater or equal to given value:

let x = 89;
query.find()
  .where('marks')
  .gte(x)
  .exec();

Also, as another answer mentioned, you can always use native MongoDB operator $gte, however Mongoose offers more intuitive approach with its chaining Query API, as above.

Also, if you're using Mongoose with Promises or async/await, don't forget to add exec() at the end - this will convert thenable-compatible Query result to a fully featured Promise, e.g.:

let x = 89;
find().where('marks').gte(x).exec()
  .then(() => {/* rest of handling*/})
  .catch(() => { /* error handling */});

The same code using async/await:

async function getResultsGreaterThan(x) {
  const results = await find().where('marks').gte(x).exec();
  console.log(results);
  return results;
}

getResultsGreaterThan(89);

More on Mongoose chainable Query API can be found in rather solid official docs https://mongoosejs.com/docs/api/query.html

I don't know what version of mongodb you are using. But this is what available in the latest releases.

$gte selects the documents where the value of the field is greater than or equal to (i.e. >=) a specified value

query.find( { marks: { $gte: 89} } )

Here

Simply use

.gte(upperlimit)

for greater than equal to and

.lte(lowerlimit)

for less than equal to.

Remember upperlimit and lowerlimit should be numeric.