Make Call in Android Application using default call application

For a generic use, you can implement like below.

Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:" + "1111111111"));
callIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);


PackageManager packageManager = context.getPackageManager();
List activities = packageManager.queryIntentActivities(callIntent, PackageManager.MATCH_DEFAULT_ONLY);

for(int j = 0 ; j < activities.size() ; j++)
{

    if(activities.get(j).toString().toLowerCase().contains("com.android.phone"))
    {
         callIntent.setPackage("com.android.phone");
    }
    else if(activities.get(j).toString().toLowerCase().contains("call"))
    {
         String pack = (activities.get(j).toString().split("[ ]")[1].split("[/]")[0]);
         callIntent.setPackage(pack);
    }
}

context.startActivity(callIntent);

Also you have to add this intent-filter to activity or receiver etc. in AndroidManifest.xml

<activity>
   <intent-filter>
      <action android:name="android.intent.action.CALL_PRIVILEGED" />
      <data android:scheme="tel" />
   </intent-filter>
</activity>

Finally don't forget to add permission to AndroidManifest.xml

<uses-permission android:name="android.permission.CALL_PHONE" />

Use intent.setPackage("com.android.phone");

Like

Intent intent = new Intent(Intent.ACTION_CALL);  
intent.setPackage("com.android.phone");               
intent.setData(Uri.parse("tel:9898989898"));
startActivity(intent);

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But better is to let the user to choose.

Read more at How to call from Android Native Dialers, ignore other dialers