List all files in array with gulp.src()

The current solution is:

var gulp = require('gulp');
var debug = require('gulp-debug');

gulp.src(sources)
  .pipe(debug());


var through = require('through2');
gulp.task('getFileList', function () {
    var fileList = [];
    gulp.src(['./someFolder/**/*.ext', '!./someFolder/unwantedFolder/**/*'])
        .pipe(through.obj(function (file, enc, cb) {
            fileList.push(file.path);
            cb(null);
        }))
        .pipe(gulp.dest('./temp/'))
        .on ('end', function () {
            console.log(fileList);
        });
});

As the OP stated in a comment, a simple solution to this problem would be to use fs.readdirSync instead of gulp.src:

fs = require("fs");
fs.readdirSync(directoryPath); // ["file1", "file2"]

Tags:

Javascript

Gulp

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