Is there a true single-pair shortest path algorithm?

Quoting CLRS, 3rd Edition, Chapter 24:

Single-pair shortest-path problem: Find a shortest path from u to v for given vertices u and v. If we solve the single-source problem with source vertex u, we solve this problem also. Moreover, all known algorithms for this problem have the same worst-case asymptotic running time as the best single-source algorithms

For non-negative weighted edges graph problem Dijkstra itself solves given problem.

A quote from wiki

The algorithm exists in many variants; Dijkstra's original variant found the shortest path between two nodes, but a more common variant fixes a single node as the "source" node and finds shortest paths from the source to all other nodes in the graph, producing a shortest-path tree.

Consider following pseudo code from wiki:

 1  function Dijkstra(Graph, source):
 2
 3      create vertex set Q
 4
 5      for each vertex v in Graph:             // Initialization
 6          dist[v] ← INFINITY                  // Unknown distance from source to v
 7          prev[v] ← UNDEFINED                 // Previous node in optimal path from source
 8          add v to Q                          // All nodes initially in Q (unvisited nodes)
 9
10      dist[source] ← 0                        // Distance from source to source
11      
12      while Q is not empty:
13          u ← vertex in Q with min dist[u]    // Node with the least distance will be selected first
14          remove u from Q 
15          
16          for each neighbor v of u:           // where v is still in Q.
17              alt ← dist[u] + length(u, v)
18              if alt < dist[v]:               // A shorter path to v has been found
19                  dist[v] ← alt 
20                  prev[v] ← u 
21
22      return dist[], prev[]

with each new iteration of while (12), first step it to pick the vertex u with shortest distance from the remaining set Q (13) and then that vertex is removed from the Q (14) notifying that shortest distance to u has been achieved. If u is your destination then you can halt without considering further edges.

Note that all vertices were used but not all edges and shortest path to all vertices was not yet found.