Interpret +p code

05AB1E, 5 bytes

vy.V,

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Explanation

This challenge fit 05AB1E like a glove :)

vy      # for each instruction in the program
  .V    # execute as 05AB1E code
    ,   # print

l,p=input()
i=j=0
while len(l)-i:print(int(all(l[i]%k for k in range(2,l[i])))if p[j]=='p'else l[i]+l[i+1]);i+=1+'p+'.find(p[j]);j+=1

-2 bytes thanks to kundor

p,i=input()
for c in p:n=i.pop(0);print all(n%k for k in range(2,n))if c>'+'else n+i.pop(0)

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