int.TryParse syntatic sugar

int intValue = int.TryParse(stringValue, out intValue) ? intValue : 0;

Maybe use an extension method:

public static class StringExtensions
{
    public static int TryParse(this string input, int valueIfNotConverted)
    {
        int value;
        if (Int32.TryParse(input, out value))
        {
            return value;
        }
        return valueIfNotConverted;
    }
}

And usage:

string x = "1234";
int value = x.TryParse(0);

Edit: And of course you can add the obvious overload that already sets the default value to zero if that is your wish.

I would create an extension method out of this.

public static int? AsInt32(this string s)
{
    int value;
    if (int.TryParse(s, out value))
        return value;

    return null;
}

This answer is only for those who use at least C# 7.

You can now declare the out parameter inline.

int.TryParse("123", out var result);

Exemplary usage:

if (int.TryParse("123", out var result)) {
    //do something with the successfully parsed integer
    Console.WriteLine(result);
} else {
    Console.WriteLine("That wasn't an integer!");
}

MSDN: https://docs.microsoft.com/en-us/dotnet/csharp/whats-new/csharp-7#out-variables