Indexing with List of Indices to Exclude

>>> to_exclude = {1, 2}
>>> vector = ['a', 'b', 'c', 'd']
>>> vector2 = [element for i, element in enumerate(vector) if i not in to_exclude]

The tricks here are:

• Use a list comprehension to transform one list into another. (You can also use the filter function, especially if the predicate you're filtering on is already lying around as a function with a nice name.)
• Use enumerate to get each element and its index together.
• Use the in operator against any Set or Sequence* type to decide which ones to filter. (A set is most efficient if there are a lot of values, and probably conceptually the right answer… But it really doesn't matter much for just a handful; if you've already got a list or tuple with 4 indices in it, that's a "Set or Sequence" too, so you can just use it.)

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* Technically, any Container will do. But most Containers that aren't a Set or Sequence would be silly here.

Use np.delete

In [38]: a
Out[38]: array([ 4,  5,  6,  7,  8,  9, 10, 11, 12, 13])

In [39]: b
Out[39]: [3, 4, 5, 9]

In [40]: a[b]
Out[40]: array([ 7,  8,  9, 13])

In [41]: np.delete(a, b)
Out[41]: array([ 4,  5,  6, 10, 11, 12])

import numpy
target_list = numpy.array(['1','b','c','d','e','f','g','h','i','j'])
to_exclude = [1,4,5]
print target_list[~numpy.in1d(range(len(target_list)),to_exclude)]

because numpy is fun