# In relativity, if units of length contracts and time dilates then does unit of velocity or speed also change?

No. Velocities do transform in a non-intuitive way in special relativity, but not in the way you're describing. This is sadly a very common misunderstanding due to the fact that Relativity is usually first introduced using time-dilation and length contraction, without actually explaining under which conditions they are applicable. The best way to begin understanding the subject (and to also avoid all these "paradoxes") is to work with the Lorentz Transformations. In one dimension, if the frame $S'$ is moving with respect to $S$ with a velocity $v$, then

\begin{aligned} x' &= \gamma\left( x - vt \right)\\ t' &= \gamma \left( t - \frac{v}{c^2}x\right) \end{aligned}

provided that $x=x'=0$ when $t=t'=0$. Remember, though, that these are *coordinates*, not intervals. To find how intervals of length and intervals of time are related, we need to take *differences* of the coordinates, and since $v$ and $\gamma$ are constants, it's easy to show that the intervals satisfy similar equations:

\begin{aligned} \Delta x' &= \gamma\left( \Delta x - v \Delta t \right)\\ \Delta t' &= \gamma\left( \Delta t - \frac{v}{c^2}\Delta x\right) \end{aligned}

We can use the above equations to easily calculate how the velocities transform between the frames $S$ and $S'$. Remember that an observer in $S$ will calculate the velocity of an object to be $$u = \frac{\Delta x}{\Delta t},$$ and one in $S'$ will calculate it to be $$u' = \frac{\Delta x'}{\Delta t'}.$$

We can now divide $\Delta x'$ by $\Delta t'$ to show that:

$$u' = \frac{\Delta x'}{\Delta t'} = \frac{u - v}{1 - \frac{uv}{c^2}}.$$

### Why doesn't your argument work?

Length contraction and time dilation are special cases of the general formulae that I have given above. They hold when certain conditions are satisfied, and these conditions are more certainly not satisfied *simultaneously*. Which means dividing the equations is not going to give you anything sensible. In special relativity, it is best to think in terms of "events" which occur at spacetime points $(t, x)$ to avoid such false "paradoxes". My answer here, and the links at the end, should explain it in more detail.