How to remove a positional parameter from $@

POSIXly:

for arg do
  shift
  [ "$arg" = "-inf" ] && continue
  set -- "$@" "$arg"
done

printf '%s\n' "$@"

The above code even works in pre-POSIX shells, except the original Almquist shell (Read Endnote). Change the for loop to:

for arg
do
  ...
done

guarantee to work in all shells.

Another POSIX one:

for arg do
  shift
  case $arg in
    (-inf) : ;;
       (*) set -- "$@" "$arg" ;;
  esac
done

With this one, you need to remove the first ( in (pattern) to make it work in pre-POSIX shells.

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