How to pass argument to script which is input to bash

I believe what you are looking for is the -s option. With -s, you can pass arguments to the script.

As a dummy example to illustrate this:

$ echo 'echo 1=$1' | bash -s -- Print
1=Print

Here, you can see that the script provided on stdin is given the positional parameter Print. Your script takes a -u UUID argument and that can be accommodated also:

$ echo 'echo arguments=$*' | bash -s -- -u UUID print
arguments=-u UUID print

So, in your case:

curl -fsSL http://git.io/vvZMn | bash -s -- print

Or,

curl -fsSL http://git.io/vvZMn | bash -s -- -u UUID print

As Stephen Harris pointed out, downloading a script and executing it, sight unseen, is a security concern.

If your system has /dev/stdin, you can use

$ echo 'echo 1=$1' | bash /dev/stdin print
1=print

Do not do this:

$ echo 'echo 1=$1' | bash /dev/stdin -- print
1=--

If you want to use --, do this:

$ echo 'echo 1=$1' | bash -- /dev/stdin print
1=print