How to override a JavaScript function

You can do it like this:

alert(parseFloat("1.1531531414")); // alerts the float
parseFloat = function(input) { return 1; };
alert(parseFloat("1.1531531414")); // alerts '1'

Check out a working example here: http://jsfiddle.net/LtjzW/1/

You can override any built-in function by just re-declaring it.

parseFloat = function(a){
  alert(a)
};

Now parseFloat(3) will alert 3.

You could override it or preferably extend it's implementation like this

parseFloat = (function(_super) {
    return function() {
        // Extend it to log the value for example that is passed
        console.log(arguments[0]);
        // Or override it by always subtracting 1 for example
        arguments[0] = arguments[0] - 1;
        return _super.apply(this, arguments);
    };         

})(parseFloat);

And call it as you would normally call it:

var result = parseFloat(1.345); // It should log the value 1.345 but get the value 0.345

var origParseFloat = parseFloat;
parseFloat = function(str) {
     alert("And I'm in your floats!");
     return origParseFloat(str);
}