How to iterate two elements in a row with ngFor

You can skip every other index just by looking for even numbers (0, the first index is even) for *ngIf, and display that items with the next soon be skipped (odd) item:

<div class='row wow fadeInUp' *ngFor='let index of myArray; let i = index; let even = even'>
      <span *ngIf="even">
         <div class='col-md-6' >
             <md-card>
                <md-card-header>
                   <md-card-title>
                     {{myArray[i]}}
                   </md-card-title>
                 </md-card-header>
              </md-card>
         </div>
         <div class='col-md-6'>
             <md-card>
                <md-card-header>
                   <md-card-title>
                     {{myArray[i+1]}}
                   </md-card-title>
                 </md-card-header>
              </md-card>
        </div>
       </span>
    </div>

DEMO EXAMPLE

ngFor exposes odd and even which can be used to conditionally (using ngIf) display some items.

<ul>
  <li *ngFor="let item of array; let even = even">
    <ng-container *ngIf="even">{{ item }}</ng-container>
  </li>
</ul>

That said, it's probably better you do this in your code instead of in the template. It's clearer, testable and more perfomant.

evenItems = array.filter((_, index) => index % 2 == 0)

Then just loop over those.

<ul>
  <li *ngFor="let item of eventItems">
    {{ item }}
  </li>
</ul>