How to get the index with the key in Python dictionary?

Use OrderedDicts: http://docs.python.org/2/library/collections.html#collections.OrderedDict

>>> x = OrderedDict((("a", "1"), ("c", '3'), ("b", "2")))
>>> x["d"] = 4
>>> x.keys().index("d")
3
>>> x.keys().index("c")
1

For those using Python 3

>>> list(x.keys()).index("c")
1

Dictionaries in python have no order. You could use a list of tuples as your data structure instead.

d = { 'a': 10, 'b': 20, 'c': 30}
newd = [('a',10), ('b',20), ('c',30)]

Then this code could be used to find the locations of keys with a specific value

locations = [i for i, t in enumerate(newd) if t[0]=='b']

>>> [1]

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